Sound Waves

Key Concepts

# Concept One-line Explanation
1 Longitudinal wave Particle vibration // to wave travel; creates C&R.
2 Speed formula v = f λ ; remember v_air ≈ 330 m s⁻¹ at 25 °C.
3 Factors affecting speed v ∝ √T (Kelvin) in gas; v_solids > v_liquids > v_gases.
4 Loudness ∝ (Amplitude)² 20 dB jump = 10× intensity; 0 dB = human threshold.
5 Pitch ∝ frequency Shrill = high f; flat = low f.
6 Quality/timbre Depends on number & relative intensity of harmonics.
7 Reflection Echo: d_min = 17 m ⇒ t ≥ 0.1 s for distinct hearing.
8 Resonance Forced f = natural f ⇒ big amplitude; breaking glass, swing.

15 Practice MCQs

(Use in tag for self-quiz)

  1. The speed of sound is maximum in which medium at 25 °C? A. Dry air
    B. Hydrogen gas
    C. Steel rail
    D. Rain water

Answer: C. Steel rail
Solids have highest modulus ⇒ highest v (≈ 5000 m s⁻¹).
Shortcut: “Solid > Liquid > Gas” – tick the solid option.
Concept tag: Speed dependence on medium.

  1. A 1 kHz wave has λ = 66 cm in air. Temperature of air is about A. −6 °C
    B. 11 °C
    C. 26 °C
    D. 41 °C

Answer: C. 26 °C
v = f λ = 1000 × 0.66 = 330 m s⁻¹ ⇒ matches 25–26 °C.
Trick: 330 m s⁻¹ ≈ room temperature; match table.
Tag: v ∝ √T.

  1. If amplitude doubles, by what factor does loudness increase? A. 2
    B. 4
    C. 6
    D. 10

Answer: B. 4
Loudness ∝ (Amplitude)².
Tag: Loudness vs amplitude.

  1. Echo is not heard in a 10 m hall because A. Absorption is high
    B. t < 0.1 s
    C. Frequency is low
    D. Reflection is weak

Answer: B. t < 0.1 s
2d = 20 m ⇒ t = 20/330 ≈ 0.06 s < 0.1 s; brain merges sound.
Trick: 17 m minimum ⇒ hall needs ≥17 m.
Tag: Reflection & echo.

  1. The voice of ladies is shrill because of A. Large amplitude
    B. High frequency
    C. High speed
    D. Large wavelength

Answer: B. High frequency
Pitch ∝ f.
Tag: Pitch.

  1. SONAR uses which characteristic of sound? A. Interference
    B. Reflection
    C. Resonance
    D. Diffraction

Answer: B. Reflection
Echo-ranging principle.
Tag: Applications.

  1. A railway platform announcement spreads around a pillar due to A. Reflection
    B. Refraction
    C. Diffraction
    D. Polarization

Answer: C. Diffraction
Bending round obstacle.
Tag: Wave behaviour.

  1. The human ear can normally hear up to A. 2 kHz
    B. 20 kHz
    C. 200 kHz
    D. 2 MHz

Answer: B. 20 kHz
Upper audible limit.
Tag: Range of hearing.

  1. Quality of musical note depends on A. Wavelength
    B. Number of overtones
    C. Speed
    D. Phase

Answer: B. Number of overtones
Timbre decided by harmonic content.
Tag: Quality.

  1. A 60 dB sound has how many times the intensity of 30 dB sound? A. 2
    B. 10
    C. 100
    D. 1000

Answer: D. 1000
30 dB → 10³ intensity ratio (10 dB = 10×).
Trick: Difference 30 dB ⇒ 10^(30/10) = 1000.
Tag: Decibel scale.

  1. In a gas, if temperature is raised 4 times (Kelvin), speed of sound A. Doubles
    B. Triples
    C. Quadruples
    D. Unchanged

Answer: A. Doubles
v ∝ √T ⇒ √4 = 2.
Tag: Speed vs temperature.

  1. A tuning fork produces 512 Hz. If prongs are loaded with wax, frequency A. Increases
    B. Decreases
    C. No change
    D. Becomes zero

Answer: B. Decreases
Added mass ↓ natural f.
Tag: Resonance & natural frequency.

  1. Ultrasonic waves are used for cleaning by virtue of A. High speed
    B. Cavitation
    C. Interference
    D. Polarization

Answer: B. Cavitation
Micro-bubble collapse scrubs surface.
Tag: Applications.

  1. Sound cannot travel through A. Iron
    B. Water
    C. Vacuum
    D. Air

Answer: C. Vacuum
Needs material medium.
Tag: Medium requirement.

  1. A thunder is heard 5 s after lightning. Distance of strike is about A. 0.33 km
    B. 1.65 km
    C. 3.3 km
    D. 16.5 km

Answer: B. 1.65 km
d = v t ≈ 330 × 5 = 1650 m = 1.65 km.
Trick: 3 s ≈ 1 km ⇒ 5 s ≈ 1.65 km.
Tag: Real-life estimation.


Speed Tricks

Situation Shortcut Example
Convert °C → v_air Add 0.6 m s⁻¹ per 1 °C above 0 °C 35 °C ⇒ 330 + 35×0.6 ≈ 351 m s⁻¹
Echo minimum distance d_min = 17 m (remember “1–7”) Hall 15 m → no echo
dB → intensity ratio 10^(ΔdB/10) 40 dB excess → 10⁴ = 10 000×
f_unknown with resonance f = v/4L (closed pipe, fundamental) 0.2 m pipe ⇒ f ≈ 330/(4×0.2) ≈ 412 Hz
Order of speed “S-L-G” (Solid-Liquid-Gas) Pick solid when asked “maximum speed”

Quick Revision

Point Detail
1 Sound = mechanical, longitudinal, needs medium.
2 v = f λ constant for fixed medium; f fixed by source.
3 In air v ≈ 332 + 0.6 T(°C) m s⁻¹.
4 Loudness in dB; 0 dB threshold, 120 dB pain.
5 Pitch depends on f; quality on harmonics.
6 Echo condition: 2d ≥ 34 m or t ≥ 0.1 s.
7 SONAR, Bats, DOLPHIN → ultrasonic reflection.
8 Ultrasonic > 20 kHz; infrasonic < 20 Hz.
9 Resonance: forced freq = natural freq → amplitude ↑.
10 Railway application: Rail-wheel flaw detection uses ultrasonic waves.

Keep this sheet on your phone; revise daily + solve 15 Q in 6 min → 85 %ile guaranteed.